WebFeb 25, 2015 · my_module is a folder not a module and you can't import a folder, try moving my_mod.py to the same folder as the cool_script.py and then doimport my_mod as mm.This is because python only looks in the current directory and sys.path, and so wont find my_mod.py unless it's in the same directory. Or you can look here for an answer telling … Web1 day ago · 5.3.3. Import hooks¶. The import machinery is designed to be extensible; the primary mechanism for this are the import hooks.There are two types of import hooks: meta hooks and import path hooks. Meta hooks are called at the start of import processing, before any other import processing has occurred, other than sys.modules cache look …
protocol buffers - Error using import in .proto file - Stack …
WebFeb 3, 2024 · from project.folder_1 import a Since project is a package for main.py and folder_1 and folder_2 are subpackages of it, you can use Intra-package References. If … WebApr 9, 2024 · import sys, os sys.path.append (os.path.join (os.path.dirname (__file__), '..', 'Common')) import Common os.path.dirname (__file__) just gives you the directory that your current python file is in, and then we navigate to 'Common/' the directory and import 'Common' the module. Share Improve this answer edited Nov 27, 2014 at 14:17 emumovies down for maintenance
5. The import system — Python 3.11.3 documentation
WebThe right way to import a module located on a parent folder, when you don't have a standard package structure, is: import os, sys CURRENT_DIR = … WebWhen you use a relative path, it is based off the currently location (obtained via Get-Location) and not the location of the script. Try this instead: $ScriptDir = Split-Path -parent $MyInvocation.MyCommand.Path Import-Module $ScriptDir\..\MasterScript\Script.ps1 WebApr 15, 2012 · Beware that this means that other directories or .py files in that directory may be loaded inadvertently. Therefore, you may want to use imp.load_source instead. It needs the filename, not a directory (to a file which the current user is allowed to read): import imp util = imp.load_source ('util', 'C:/full/path/foo/util.py') Share emumovies black friday